Posted by Someone on February 01, 19100 at 18:48:57:

In Reply to: UP posted by Bigelow on November 29, 1999 at 15:35:59:

Um, I'm new to here and a little late, it seems, seeing from the date of the last message. However, I will answer it anyway.

It does not have any significant macroscopic effect. I'm not sure how to explain why, but I'll try anyway.

The uncertainty ociated with a single subatomic particle, is in such a way that although you cannot measure the position or momentum of the particle accurately, you can determine a range of values which it might fit. This range of values is usually relatively small, which means, of course, that the particle is always in the vicinity of any value you pick from the range.

Now, a macroscopic solid object, such as a sphere, is made up of many of these particles. And most of these particles are in the most predictable, or logical, positions. Those that are not, are usually very little in number, and produce very insignificant effects on the object as a whole.

I'm not sure if I've explained correctly, or actually got it right, but I think this is it.

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